PINKY SPENT 3/5 OF HER MONEY ON A HAND BAG. SHE SPENT REST OF THE MONEY ON A DRESS AND A BELT. THE HAND BAG COSTS TWICE AS MUCH AS THE DRESS. THE DRESS COSTS RUPEES 20 MORE THAN THE BELT. SO HOW MUCH MONEY WAS IN THE BEGNING PINKY HAVE ?

Let the total money she had be X

So, cost of hand bag = 3/5x
Cost of dress and belt together remaining of x = 2/5x
Cost of hand bag = 2 ( cost of dress)
H = 2 d and cost of dress = cost of belt +20
D = b+20,
D+ b = 2/5x
D - b = 20
Adding, we get
2d = 2/5 x + 20
= 3/5 x
= 3/5 x = 2/5 x +20
= 1/5 x = 20
= x = 100

100 answer

To determine how much money Pinky had in the beginning, we can start by creating equations based on the given information.

Let's assume that the total amount of money Pinky had in the beginning is "x" rupees.

According to the information given:
Pinky spent 3/5 of her money on a handbag.

This means she has 2/5 of her money remaining, which she spent on a dress and a belt.

Now, let's represent the cost of the handbag as "h", the cost of the dress as "d", and the cost of the belt as "b".

We're given that the handbag cost twice as much as the dress, so we can write the equation:
h = 2d

We're also told that the dress cost 20 more rupees than the belt, so we can write the equation:
d = b + 20

Since Pinky spent 2/5 of her money on the dress and the belt, we can write another equation:
d + b = (2/5)x

Now we can solve these equations to find the value of "x", which represents the total amount of money Pinky had in the beginning.

Substitute the value of "d" from the second equation into the first equation:
h = 2(b + 20)

Expand the equation:
h = 2b + 40

Since she spent 3/5 of her money on the handbag, we can write another equation:
h = (3/5)x

Now we have two equations for "h":
h = (3/5)x
h = 2b + 40

Since both equations equal "h", they must be equal to each other:
(3/5)x = 2b + 40

Now we can substitute the value of "h" from the first equation into the second equation:
(3/5)x = 2(b + 20)

Simplify the equation by distributing:
(3/5)x = 2b + 40
(3/5)x = 2b + 40

Multiply both sides by 5 to eliminate the fraction:
3x = 10b + 200

We also know that d + b = (2/5)x, so we can substitute the value of "d" into the equation:
(b + 20) + b = (2/5)x

Simplify the equation:
2b + 20 = (2/5)x

Now we have two equations:
3x = 10b + 200
2b + 20 = (2/5)x

We can solve this system of equations to find the values of "x" and "b".

Multiply the second equation by 5 to eliminate the fraction:
10b + 100 = 2x

Now we have a system of equations:
3x = 10b + 200
10b + 100 = 2x

We can use substitution or elimination method to solve this system.

Let's use substitution method:
Rearrange the second equation to isolate "b":
10b = 2x - 100
b = (2x - 100)/10
b = (x - 50)/5

Substitute this value of "b" into the first equation:
3x = 10((x - 50)/5) + 200

Simplify the equation:
3x = 2(x - 50) + 200
3x = 2x - 100 + 200
3x - 2x = 100 + 200
x = 300

Therefore, Pinky had 300 rupees in the beginning.

come on. Just read the words, and translate them into symbols.

PINKY SPENT 3/5 OF HER MONEY ON A HAND BAG.
that means that the remaining 2/5 was spent on the dress and belt.

2/5 is 2/3 of 3/5, so

d+b = (2/3) h

The other equations are also just restatements of the words in symbols.

d = b+20

h = 2d
d+b = (2/3)h

now, find b,d,h and their sum is the total money to start with.

CAN U DETAIL IT PLS