Plz, i need the workings. An object is acted upon by two forces of 5N and 12N. Calculate the resultant of two forces if the forces acting perpendicular to each other
ever see a 5-12-13 right triangle?
To calculate the resultant of two forces that are acting perpendicular to each other, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, since the forces are acting perpendicularly, we can treat them as the two sides of a right-angled triangle. The two forces can be represented as vectors, where the length of each vector represents the magnitude of the force, and the direction of the vector represents the direction of the force.
Let's label the two forces as F1 and F2. In this case, F1 has a magnitude of 5N and F2 has a magnitude of 12N.
Using the Pythagorean theorem, we can calculate the resultant force (R) as follows:
R^2 = F1^2 + F2^2
Substituting the values, we have:
R^2 = (5N)^2 + (12N)^2
R^2 = 25N^2 + 144N^2
R^2 = 169N^2
Taking the square root of both sides, we find:
R = √(169N^2)
R = 13N
Therefore, the resultant of the two forces is 13N.
To recap the steps:
1. Identify the two forces acting perpendicular to each other (F1 and F2).
2. Square the magnitude of each force.
3. Add the squared values together.
4. Take the square root of the sum to find the magnitude of the resultant force.