A chemist determined by measurements that

0.0850
moles of mercury participated in a chemical reaction. Calculate the mass of mercury that participated in the chemical reaction.
Round your answer to
3
significant digits.

A chemist determined by measurements that 0.0850 moles of aluminum participated in a chemical reaction. Calculate the mass of aluminum that participated in the chemical reaction.�Be sure your answer has the correct number of significant digits.

To calculate the mass of mercury that participated in the chemical reaction, we need to use the molar mass of mercury. The molar mass of mercury is the mass of one mole of mercury atoms, which is equal to its atomic mass.

The atomic mass of mercury is 200.59 grams per mole. Therefore, to calculate the mass of mercury, we can use the following formula:

Mass = moles x molar mass

Plugging in the given values:

Mass = 0.0850 moles x 200.59 g/mol

Mass = 17.05 grams

Since we need to round our answer to 3 significant digits, the final answer is 17.1 grams.

grams Hg = mols Hg x atomic mass Hg.

Then round to 3 s.f. Post your work if you get stuck.

HELB

21.6. Idk how I just did it on ALEKS and got it wrong and thats what the explanation said lol

17g of gold

1.20