The electrons that produce the picture in a TV set are accelerated by a very large electric force as they pass through a small region in the neck of the picture tube. This region is

1.4 cm in length, and the electrons enter with a speed of 1× 105 m/s and leave with a speed of 1.5 × 108 m/s.

a. What is their acceleration over this 1.4 cm length? Answer in units of m/s2.

b. How long is the electron in the accelerating region? Answer in units of s.

Tip: Write down the values you have and are looking for:

s=1.4cm
v=1*105m/s
u=1.5*108m/s
You must use an equation like s=v-ut/2, in order to find the time.
Isolate the t.

a. Why did the electron cross the road? To accelerate, of course!

To calculate the acceleration, we can use the formula:

acceleration = (change in velocity) / (change in time)

The change in velocity is the final velocity minus the initial velocity:

change in velocity = (1.5 × 10^8 m/s) - (1 × 10^5 m/s) = 1.499 × 10^8 m/s

Now, we need to convert the length from centimeters to meters:

length = 1.4 cm = 0.014 m

We can rearrange the formula to solve for the acceleration:

acceleration = (change in velocity) / (length)

acceleration = (1.499 × 10^8 m/s) / (0.014 m) ≈ 1.07 × 10^10 m/s^2

So, the acceleration of the electrons over this 1.4 cm length is approximately 1.07 × 10^10 m/s^2.

b. How long is the electron in the accelerating region? Well, it seems like the electron has a quicker exit strategy than most! To find out how long it stays in the region, we can use the formula:

time = (length) / (speed)

time = (0.014 m) / (1.5 × 10^8 m/s) ≈ 9.33 × 10^-11 s

Therefore, the electron stays in the accelerating region for approximately 9.33 × 10^-11 seconds.

To find the acceleration of the electrons, we can use the formula:

acceleration = (change in velocity) / (time taken)

To find the change in velocity, we subtract the initial velocity from the final velocity:

change in velocity = final velocity - initial velocity

Given:
Initial velocity, u = 1 × 10^5 m/s
Final velocity, v = 1.5 × 10^8 m/s
Length, s = 1.4 cm = 0.014 m (converted to meters)

a. To find the acceleration, we use the formula:

acceleration = (final velocity - initial velocity) / (time taken)

Since the length is given and we need to find the time taken, we can rearrange the formula to solve for time:

time taken = length / (final velocity - initial velocity)

Substituting the given values:

time taken = 0.014 m / (1.5 × 10^8 m/s - 1 × 10^5 m/s)

Calculating the time taken:

time taken ≈ 9.34 × 10^-11 s

Now that we have the time taken, we can calculate the acceleration:

acceleration = (final velocity - initial velocity) / (time taken)
acceleration = (1.5 × 10^8 m/s - 1 × 10^5 m/s) / (9.34 × 10^-11 s)

Calculating the acceleration:

acceleration ≈ 1.424 × 10^17 m/s^2

Therefore, the acceleration of the electrons over the 1.4 cm length is approximately 1.424 × 10^17 m/s^2.

b. To find the time it takes for the electron to pass through the accelerating region, we already calculated the time taken as 9.34 × 10^-11 s.

Therefore, the electron is in the accelerating region for approximately 9.34 × 10^-11 seconds.

i did not understand that! I NEED HELP!

BE CAREFUL OF UNITS

The neck length is in cm!

For a constant acceleration:
s = distance
v1 = initial velocity
v2 = final velocity
a = acceleration
t = time

s = (v1)(t) + (1/2)(a)(t^2)
s and v1 are given

v2 = v1 + (a)(t)
so (a)(t) = v2 - v1
v1 and v2 are given
substitute for (a)(t) in the first equation to solve for time.
acceleration = dv/dt = (v2 - v1)/t