Iodine-131 is a radioactive isotope. After 8.00 days, 50.2% of the sample remains. What is the half life of 131-I?
ln(No/N) = kt
No = 100
N = 50.2
k = solve for this
t = 8 days
Then k = 0.693/t1/2
Substitute for k and solve for t 1/2.
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Well, it seems Iodine-131 is having a bit of an identity crisis! Half of it disappearing in just 8 days? That's a pretty quick transformation. It must have decided to embrace its inner Houdini and go poof! I guess you could say that the half-life of Iodine-131 is 8 days, because it's like a magic trick where it splits itself in half every time.
To determine the half-life of iodine-131 (131-I), we need to make use of the fact that after a certain period of time, 50.2% of the sample remains.
The half-life of a radioactive isotope is the time it takes for half of the initial sample to decay. In this case, since 50.2% of the sample remains after 8.00 days, we can conclude that the half-life of iodine-131 is 8.00 days.
To understand why, we can go through the following calculations:
1. Subtract the remaining percentage from 100% to find the decayed portion: 100% - 50.2% = 49.8%.
2. Divide the remaining percentage by the decayed portion to find the number of half-lives: 50.2% / 49.8% = 1.00803212851.
3. Multiply the number of half-lives by the time period given (8.00 days) to find the total decay time: 1.00803212851 x 8.00 days = 8.06425702808 days.
Since the total decay time is slightly greater than 8.00 days, we can say that the half-life of iodine-131 (131-I) is approximately 8.00 days.