A rectangular room is 4.15 meters longer than it is wide, and its perimeter is 27.9 meters. Find the dimensions of the room.
The length is :-------- meters and the width is -----meters.
Nina/Mya -- Please use the same name for your posts.
P = 2L + 2W
width --- w
length --- l = w + 4.15
use Ms Sue's formula
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To find the dimensions of the room, we can set up a system of equations based on the given information.
Let's let "x" represent the width of the room in meters.
According to the problem, the length of the room is 4.15 meters longer than its width. So, the length would be "x + 4.15" meters.
The perimeter of a rectangle is found by adding up all the sides. In this case, we have two lengths and two widths, so the perimeter equation would be:
2(width) + 2(length) = perimeter
Substituting the values we have:
2(x) + 2(x + 4.15) = 27.9
Now, we can solve this equation to find the value of "x" (the width).
2x + 2x + 8.3 = 27.9
4x + 8.3 = 27.9
4x = 19.6
x = 4.9
Therefore, the width of the room is 4.9 meters.
We can now find the length by adding 4.15 meters to the width:
Length = 4.9 + 4.15 = 9.05 meters
So, the dimensions of the room are 9.05 meters (length) and 4.9 meters (width).