A car takes 11 s to go from v=0m/s to v = 22 m/s at constant acceleration.
If you wish to find the distance traveled using the equation d=1/2at2, what value should you use for a?
Express your answer to two significant figures and include the appropriate units.
please help me on the units
Well, to find the value of a, we can rearrange the equation d = 1/2at^2 to solve for a. By substituting the known values, we have:
22 m/s = 1/2 * a * (11 s)^2
Let's solve for a:
a = (2 * 22 m/s) / (11 s)^2
a = 4 m/s²
So, the value of a is 4 m/s². Keep in mind that the units for acceleration are meters per second squared (m/s²). And don't worry, you won't need a clown car to solve this problem!
To find the distance traveled using the equation d = 1/2at^2, we need to determine the acceleration (a) value.
Given that the car takes 11 s to go from v = 0 m/s to v = 22 m/s at a constant acceleration, we can use the equation v = at to find the acceleration.
Rearranging the equation, we have a = v / t, where v = 22 m/s and t = 11 s.
Substituting the values, we get a = 22 m/s / 11 s = 2 m/s².
Therefore, the value for acceleration (a) to be used in the equation d = 1/2at^2 is 2 m/s².
For the units, "m/s²" represents meters per second squared, which is a unit of acceleration.
think about it. If it takes 11 seconds for the speed to go from 0 to 22, clearly, the speed grows by 2 each second.
So, a = (2m/s)/s = 2 m/s^2