Calculate the percentage by mass of the active ingredient in an antacid tablet that weighs 1.36 g if it contains 520 mg of calcium carbonate
What is the total dose required for a 140 lb patient if the amount required is 28 mg/kg bodyweight?
At 28.2 C, a 208 g sample of a metal absorbs 1.75 kJ of heat (q). The specific heat (Cs) of this
metal is 0.137 J/g oC. what is the final temperature of the metal?
percent=.520/1.36 x 100
dose=140lb*1kg/2.2lb * 28mg/kg
Q=mc(tf-ti)
solve for Tf
To calculate the percentage by mass of the active ingredient, which in this case is calcium carbonate, in the antacid tablet, you need to divide the mass of the active ingredient by the total mass of the tablet and multiply the result by 100.
Step 1: Convert the mass of calcium carbonate from milligrams (mg) to grams (g).
520 mg = 520/1000 = 0.52 g
Step 2: Calculate the percentage by mass.
Percentage by Mass = (Mass of Active Ingredient / Total Mass of Tablet) x 100
Mass of Active Ingredient = 0.52 g
Total Mass of Tablet = 1.36 g
Percentage by Mass = (0.52 g / 1.36 g) x 100
Percentage by Mass = 38.24%
Therefore, the percentage by mass of the active ingredient, calcium carbonate, in the antacid tablet is approximately 38.24%.