If one third of 100 g of 27% aqueous sugar solution

is taken in a beaker and 10 g of sugar is added to
it, the concentration of the resulting solution will be

Rdf

if one third of 100 g of 27% aqueous sugar solution is taken in a beaker and 10 g of sugar is added to it, the concentration of the resulting solution will be 43.84%

43.84

43.8

what is the answer

Explain briefly how it is 43.84%

To find the concentration of the resulting solution, we need to calculate the amount of sugar present in the solution after adding 10 g of sugar.

First, let's find the initial amount of sugar in the solution:
The initial solution is 100 g of a 27% sugar solution, which means it contains 27 g of sugar. This can be calculated by multiplying the total weight (100 g) by the percentage of sugar (27/100).

Next, let's find the amount of solution taken in the beaker:
One-third of 100 g is (1/3) * 100 = 33.33 g (rounded to two decimal places).

Now, let's add 10 g of sugar to this amount of solution taken in the beaker:
The amount of sugar in the beaker is 33.33 g * (27/100) = 9 g (rounded to one decimal place).
Adding 10 g of sugar to this gives a total of 9 g + 10 g = 19 g of sugar.

Finally, let's find the concentration of the resulting solution:
The total amount of solution after adding 10 g of sugar is 33.33 g + 10 g = 43.33 g (rounded to two decimal places).
The concentration is calculated by dividing the amount of sugar (19 g) by the total weight of the solution (43.33 g) and multiplying by 100 to get the percentage: (19/43.33) * 100 ≈ 43.85% (rounded to two decimal places).

Therefore, the concentration of the resulting solution will be approximately 43.85%.