An athlete swims from the North end to the South end of a 50.0 Meter pool in 20.0 seconds, and makes the return trip to the starting point in 20.0s

A. What is the average velocity for the first half of the swim

B.What is the average velocity for the seconds half of the swim

C. What is the average velocity for the round trip?

Not asking for an answer, atleast a formula or the directions of HOW to solve it?

A. V=d/t = 50m/20s = 2.5 m/s north

B. V=d/t = 50m/22s = 2.27 m/s south
C. V= 50m-50m/20s+22s = 0m/s
Im not sure of c.

A is south and b is north

Sorry i made a mistake

A. To calculate the average velocity for the first half of the swim, you need to determine the displacement and divide it by the time taken.

The displacement for the first half of the swim is the distance from the North end to the South end, which is 50.0 meters.

The time taken is 20.0 seconds.

Therefore, the average velocity for the first half of the swim can be calculated using the formula:

Average velocity = Displacement / Time taken

B. Finding the average velocity for the second half of the swim follows the same process as for the first half. The displacement remains the same (50.0 meters), but the time taken is still 20.0 seconds.

Average velocity = Displacement / Time taken

C. To find the average velocity for the round trip, you can use the overall displacement and the total time taken.

The overall displacement is zero because the swimmer returns to the starting point, so the displacement is equal to 0 meters.

The total time taken for the round trip is 20.0 seconds for the first half and 20.0 seconds for the second half, which gives a total of 40.0 seconds.

Average velocity = Displacement / Time taken

Remember, displacement is zero here because the swimmer returns to the starting point.

To find the average velocity for each part of the swim as well as the round trip, you need to use the formula:

Average Velocity = Displacement / Time

To calculate the displacement for each part of the swim, use the formula:

Displacement = Final Position - Initial Position

For the first half of the swim:

1. The initial position is the North end of the pool, which we can represent as x₀ = 0.
2. The final position is the South end of the pool, which we can represent as x₁ = 50.0 meters.
3. The time taken for the first half of the swim is 20.0 seconds.

Using these values, you can calculate the displacement for the first half of the swim:

Displacement = x₁ - x₀ = 50.0 m - 0 = 50.0 m

Now, you can use the formula for average velocity to find the average velocity for the first half of the swim:

Average Velocity (first half) = Displacement / Time

For the second half of the swim, you can use a similar approach. The initial position is x₀ = 50.0 meters (the South end of the pool), and the final position is x₁ = 0 (the North end of the pool). The time taken for the second half of the swim is also 20.0 seconds.

Displacement (second half) = x₁ - x₀ = 0 - 50.0 m = -50.0 m (since the swimmer is moving in the opposite direction)

Average Velocity (second half) = Displacement (second half) / Time

To find the average velocity for the round trip, you can use the total displacement and the total time taken for the round trip. The total displacement is the sum of the displacements for the first and second halves:

Total Displacement = Displacement (first half) + Displacement (second half)

Total Time = Time (first half) + Time (second half)

Average Velocity (round trip) = Total Displacement / Total Time

Using these formulas, you can calculate the average velocities for the different parts of the swim.

worst answer

A. V = d/t = 50m/10s. = 5 m/s.

B. = V = 50m/10s = 5 m/s.

C. V = 100m/20s = 5 m/s.