Ask questions and get helpful answers.

A skier slides horizontally along the snow for a distance of 12.1 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.0343. Initially, how fast was the skier going?

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

1 answer

  1. a = u*g = 0.0343 * (-9.8) = -0.336 m/s^2.

    V^2 = Vo^2 + 2a*d = 0.
    Vo^2 = -2a*d = -2*(-0.336)*12.1 = 8.13.
    Vo = 2.85 m/s.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.