What is the area of rectangle wxyz with vertices w(0,1),x(3,4),y(-1,8) z (-4,5) to the nearest unit?

if you trust that the vertices do in fact form a rectangle, then just find the lengths of sides wx and wz

wx has length 3√2
wz has length 4√2

the rectangle thus has area 24

Hello Steve!

To help everyone else who come across this problem and still don't get it like me,

to find the "lengths" you will have to use the Distance Formula.

d = �ã(x2 - x1)^2 +(y2 - y1)^2)

so, just insert the wx values in this and then do it again for the wz values and times the two values together to get your answer. Hoped I helped!! :)

24 square units

1 is b.22 in.

2 is b. 20 ft.
3 is d. 24 square units

That's all I have so far

*the symbol won't show for me, sorry!**

d = (square root)((x2 - x1)^2 +(y2 - y1)^2)

dose anyone got all the answers im so behind

*d = �ã(x2 - x1)^2 +(y2 - y1)^2)

24

J

thank you