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A rectangle is 12 cm longer than it is wide. a wooden walk 2 ft wide is placed around the pond. the area covered by the pond and walk is 160 ft^2 greater than the area covered by the pond alone. What are the dimensions of the pond

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twnkal eshaal
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  1. I suspect that the pond is 12 ft longer than it is wide. 12 cm is a ridiculous amount. Assuming that, we have the dimensions of w and w+12.

    Then we are told that

    (w+4)(w+12+4) - (w)(w+12) = 160
    Solve that and you find w=12.

    So, the pond is 12x24

    16*28 - 12*24 = 160

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    Steve

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