A grocer wishes to blend two different coffee brands because he wants to make a blend of 480 pounds to sell at $2.68 a pound. If he uses a brand of coffee worth $2.50 a pound with another brand worth $2.80 a pound, how many pounds of each does he use?

how did you get that ??

2.5x + 2.8(480-x) = 2.68(480)
2.5x + 1344 - 2.8x = 128.40
-.3x = -57.6
x = 192

so he should use 192 pounds of the $2.50 and
288 pounds of the $2.80 stuff

check:
cost of the parts = 2.5(192) + 2.8(288) = 1286.40
cost of the mix = 2.68(480) = 1286.40

my answer is correct

Got the answer, I’m way too late, but for the $2.50, it’s 192 pounds, and for the $2.80, it’s 288 pounds.

Reino, you ain’t correct sorry

Meant Reiny, autocorrect

Reiny is not correct.

nickie crrtc

To find out how many pounds of each coffee brand the grocer should use, we can set up a system of equations.

Let's say the grocer uses x pounds of the $2.50 per pound coffee brand and y pounds of the $2.80 per pound coffee brand.

Since the grocer wants to make a blend of 480 pounds, the first equation will be:
x + y = 480

The total cost of the blend will be the sum of the cost of each coffee brand:
2.50x + 2.80y = 2.68 * 480

Now we have a system of two equations:
Equation 1: x + y = 480
Equation 2: 2.50x + 2.80y = 2.68 * 480

To solve this system, we can use a method called substitution:

1. Solve Equation 1 for x in terms of y:
x = 480 - y

2. Substitute x in Equation 2 with its value:
2.50(480 - y) + 2.80y = 2.68 * 480

3. Simplify and solve for y:
1200 - 2.50y + 2.80y = 1286.40
0.30y = 86.4
y = 86.4 / 0.30
y ≈ 288

Now that we have the value for y, we can substitute it into Equation 1 to find x:
x + 288 = 480
x = 480 - 288
x = 192

Therefore, the grocer should use 192 pounds of the $2.50 per pound coffee brand and 288 pounds of the $2.80 per pound coffee brand to make the desired blend.

The wouldn't it be 1.5x+1344=1286.5

let the $2.50 stuff be x

solve for x

2.5x + 2.8(480-x) = 2.68(480)