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A picture hangs on the wall suspended by two strings, as shown in the

figure, with θ = 65°. The tension in string 1 is 1.3 N.
(a)Is the tension in string 2 greater than, less than, or equal to the tension in string 1? Explain.
(b) Verify your answer to part (a) by calculating the tension in string 2
(c) What is the weight of the picture?

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4 answers
  1. A baseball player slides into third base with an initial speed of 7.75 m/s. If the coefficient of kinetic friction between the player and the ground is 0.45, how far does the player slide before coming to rest?

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  2. 1. Are the two strings tied to the same point on the wall?

    2. a = u*g = 0.45 * (-9.8)=-4.41 m/s^2.

    V^2 = Vo^2 + 2a*d.
    V = 0.
    Vo = 7.75 m/s.
    a = 4.41 m/s^2.
    Solve for d.

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  3. 1a. 1.3*Cos(180-65) = -T2*Cos65.
    -0.549 = -0.423T2.
    T2 = 1.30 N.

    The Tensions are equal because the angles are equal.

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  4. Ti*sin(180-65) + T2*sin65 = -Wp*sin270.
    1.3*0.90631 + 1.3*90,631 = Wp.
    Wp = 2.36 N. = Wt. of picture.

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