A number rounds off 4000 the digit in the hundred places is twice the digit in the tens place. The sum of the digit is 12 . the number uses only two different digits .find the number

I assume you are rounding to the nearest thousand

since it rounds to 4000, the hundreds digit could only be 0,1,2,3, or 4 if the number starts with a 4
or
only 5,6,7,8,9 if it starts with a 3
but the hundreds digit is twice the tens, so the hundreds digit must be even

so cases:
363X , sum of digits so far is 12 , so # is 3630
384X , sum of digits so far is 15 , not possible
421X , sum of digits so far is 7 , so # is 4215
442X, sum of digits so far is 10 , so # is 4422

so it could be 3630, 4215, or 4422

4422

6+11+9=26

6+12+8=26
6+13+7= 26

6119, 6128 & 6137 are all rounded in the nearest thousand to 6000

To find the number, let's break down the given information step by step:

1. The number rounds off to 4000. This means the number is closer to 4000 than any other number. Therefore, the number must be between 3950 and 4049.

2. The digit in the hundred places is twice the digit in the tens place. Let's denote the tens digit as "x". Therefore, the hundreds digit must be "2x". Since the sum of the digits is 12, we can write the equation: 2x + x + 0 + 0 = 12, which simplifies to 3x = 12.

3. Solving the equation 3x = 12 gives us x = 4. Therefore, the tens digit (x) is 4, and the hundreds digit (2x) is 8.

4. The number uses only two different digits. Since we know the hundreds digit is 8, the only other possible digit is 0, as it hasn't been used yet.

Therefore, the number is 8400.

A number rounds off 4000 the digit in the hundred places is twice the digit in the tens place. The sum of the digit is 12 . the number uses only two different digits .find the number

What number whose sum of its digits is 26, becomes 6000, when rounded to the nearest thousand? list 3 possible asnswer

rounded number