a bullet moving with a velocity of 10m/s is stopped after penetrating the wooden plank of 4 cm of thickness. calculate acceleration of the bullet

initial velocity=10m/s

final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250

V^2 = Vo^2 + 2a*d = 0

10^2 + 2a*0.04 = 0
2a*0.04 = -100
a = -1250 m/s.

Note: The negative sign means that the
acceleration opposes the motion.

initial velocity=10m/s

final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250

initial velocity=10m/s

final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250

To calculate the acceleration of the bullet, we need to know the initial velocity, the final velocity, and the distance it traveled.

Given:
- Initial velocity (u) = 10 m/s
- Distance traveled (d) = 4 cm = 0.04 m
- Final velocity (v) = 0 m/s (since the bullet is stopped)

We can use the following kinematic equation to calculate the acceleration (a):

v^2 = u^2 + 2ad

Rearranging this equation, we get:

a = (v^2 - u^2) / (2d)

Substituting the values:

a = (0^2 - 10^2) / (2 * 0.04)

a = -100 / 0.08

a = -1250 m/s^2

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, which means the bullet is decelerating.

Therefore, the acceleration of the bullet is approximately -1250 m/s^2.

initial velocity=10m/s

final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-125