A pistol is fired horizontally toward a target 120 m away but at the same height. The bullet's velocity is 200 m/s. How long does it take the bullet to get to the target? How far below the target does the bullet hit?
please explain why you used the formula and how you got the answer.
it takes 120/200 = .6 seconds to reach the target.
So, how far does the bullet fall in .6 s?
would it be ~
Delta(y)= 1/2(9.8m/s^2)(.6s)^2 = 1.764 so it would be about 5 feet off? That's quite a miss..
Could you specify the 120/200? is it just Delta(t)= 120/200 ? i want to set it up right.
height fell=1/2 g t^2, and your about 5 feet is correct.