One cell phone plan costs $15 per month plus $0.10 per minute used. A second cell phone plan costs $50 per month for unlimited use. Write and solve an inequality to find when the second plan is cheaper than the first.

you want m where

50 < 15+.10m

A cellphone service provider charges​ $5.00 per month and​ $0.10 per minute per call. If a​ customer's current bill is​ $50.00, how many calling minutes did the customer​ use?

A.
500 minutes
B.
450 minutes
C.
550 minutes
D.
400 minutes

To find when the second plan is cheaper than the first, we need to compare the costs of the two plans.

Let's assume the number of minutes used per month is represented by the variable "m".

For the first plan, the cost per month is $15 plus $0.10 per minute. So the total cost for the first plan is 15 + 0.10m.

For the second plan, the cost per month is a fixed $50.

To find when the second plan is cheaper than the first, we can set up the inequality:

50 < 15 + 0.10m

Now, let's solve the inequality to find when the second plan is cheaper:

Subtract 15 from both sides of the inequality:
50 - 15 < 15 + 0.10m - 15
35 < 0.10m

Divide both sides of the inequality by 0.10:
35 / 0.10 < (0.10m) / 0.10
350 < m

Therefore, the second plan is cheaper than the first when the number of minutes used per month is greater than 350.