a cylindrical container has a diameter of 14cm and a height of 20cm and is full of water. The water is poured into another cylinder which has a diameter of 20cm. How deep is the water in the second cylinder?
V = π r^2 h = π (14/2)^2 * 20 = π 49 * 20 = 980 π
980 π = π (10)^2 * h
980 = 100h
Solve for h.
9.8cm
9.8cm
9.8
9.8cm
V=πr2h
V=IST cylinder=2nd cylinder
22/7*49*20=22/7*100*h
49*20=100h
980=100h
H=9.8cm2
Formula 22
8.9cm
The height of the water in the second cylinder is 9.8 cm.
3.14*20
=62.
=62.8/14
=4.4cmcube