If (1 / 49)^ n + 3 = radical (7), then n=?
F. - 7 / 4
G. 9 / 4
H. -11 / 4
J. -13 / 4
K. 15 / 4
in posers of 7, you have
7^(-2n) + 3 = 7^(1/2)
Now, in general, that's tough. I suspect you meant
(1/49)^(n+3) = √7
Then we have
7^(-2(n+3)) = 7^(1/2)
-2(n+3) = 1/2
n+3 = -1/4
n = -13/4