a-5 digit number has 7 in its tens place.The digit in ones place is 5 less than its digit at tens place.The hundreds place digit is 4 times the digit at ones place.The digit at thousands place is the same as hundreds place.Guess the digit at ten thousands place if the sum of all digit is 33.Write the number in standard form.

Tens = 7

Ones = five less than the tens = 2
Hundreds = four times the ones = 8
Thousands = same as hundreds = 8

Let n = ten thousands digit
If their sum is 33,
n + 7 + 2 + 8 + 8 = 33
n = 8

Thus the number is 88,872
Hope this helps~ `u`

To solve this problem, let's break it down step by step:

Step 1: The number has 7 in its tens place.
Let's represent the number as _ _ 7 _ _, where the underscore represents digits that we don't know yet.

Step 2: The digit in the ones place is 5 less than the digit at the tens place.
This means that the digit in the ones place is 7 - 5 = 2.

So far, our number is _ _ 7 2 _.

Step 3: The hundreds place digit is 4 times the digit in the ones place.
The digit in the ones place is 2, so the digit in the hundreds place is 4 * 2 = 8.

Now our number becomes _ 8 7 2 _.

Step 4: The digit at the thousands place is the same as the hundreds place.
We know that the hundreds place digit is 8, so the thousands place digit is also 8.

Now our number becomes 8 8 7 2 _.

Step 5: The sum of all digits is 33.
Let's calculate the sum of the known digits: 8 + 8 + 7 + 2 = 25.
To make the sum equal to 33, the digit at the ten thousands place must be 33 - 25 = 8.

So, the number in standard form is 88,728.