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A new car is purchased for the price of $35,000. If the value of the car depreciates at a rate of 12% per year, when will the car be worth half of the original rate?

I put down (this was wrong): 35000 (0.12/12) = 75000
350 (0.12/12) 175 = 612.5
= about 6 years

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Bri
1 answer

  1. V = Vo(1-r)^t = 35,000/2
    35,000(1-0.12)^t = 17,500
    Divide both sides by 35,000:
    (0.88)^t = 0.5
    Take Log of both sides:
    t*Log(0.88) = Log 0.5
    t = Log 0.5/Log(0.88) = 5.42 Years.

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    Henry

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