The volumes of two similar solids are 1,331 m^3 and 216 m^3. The surface area of the larger solid is 484 m^2. What is the surface area of the smaller solid?
A. 864m^2
B. 288m^2
C. 144m^2
D. 68m^2
I think the answer is B or C just a lil confused...
V = k x^3
A = c x^2
for big one xb^3 = 1331/k
for small one xs^3 = 216/k
or
xb/xs = (1331/216)^(1/3)= 1.83333333....
so
xb^2/xs^2 = area ratio = 3.361111....
484/3.361111... = 144
Im pretty sure 17 is actually 1:8, instead of 1:4
(The answers switch up all the time btw so the questions may be a little different)
Oml this is my first time seein recent replies
I submitted my test and these were the answers
1. B 15
2. C Hexagon
3. D 95 cm^2 ; 275cm^2
4. C 795 m^2 ; 822 m^2
5. B 2,205
6. B 770
7. B 29.9 cm
8. C LA = 1,1887 ft^2 ; SA = 1,803 ft^2
9. B 593.9 cm^3
10. D 39.71 pi m^3
11. D 3.6 in
12. C 528 cm^3
13. C 1,368 cm^3
14. C 168 cm^2
15. B 2,145
16. C 2,158
17. A yes 1:4
18. C 144 m^2
19. A 49,009 m^2
20. A 576 cm^3
Some of my answers are different than "Correct answers" so, here are my test answers.
U6 L10 Surface Area and Volume Unit Test
1. B, 15
2. A, pentagon
3. B, 112 cm^2; 448 cm^2
4. C, 795 m^2; 822 m^2
5. C, 2,187 in^2
6. D, 790 m^2
7. A, 36.8 cm
8. A, LA = 829.4 ft^2; SA = 1,209.5 ft^2
9. B, 593.9 cm^3
10. B, 58.08pi m^3
11. D, 3.6 in
12. A, 507 cm^3
13. B, 1,512 cm^3
14. A, 115 cm^2
15. A, 3,054 cm^3
16. B, 3,033 m^2
17. A, yes; 1:4
18. C, 144 m^2
19. A, 49,009 m^2
20. C, 1,944 cm^3
So I took the test twice and had some of the same questions and some of them were different here are the answers to both find what matches your chose for the second one I would look at the picture before putting hexagon or trapezoid because they have the same answers inline
11
trapezoid
137,307
859,891
2187
790
43.1
829.4,1209.5
593.9
39.71
2.4
392
1,512
115
3,054
3,033
yes 1:4
144
4,712
4608
the second set of answers
11
hexagon
112,336
795,822
2187
1125
29.9
1187.5,1803.3
6171
58.08
2.4
528
850
168
5575
3033
yes1:4
196
4712
4608
that's it
" I'M THE ANSWER MAN DO YOU KNOW THE ANSWER"
To find the surface area of the smaller solid, you can use the concept of similarity between the two solids.
The volumes of two similar solids are proportional to the cubes of their corresponding lengths. So we have the following relationship:
(volume of the larger solid) / (volume of the smaller solid) = (length of the larger solid)³ / (length of the smaller solid)³
Given that the volumes of the two similar solids are 1,331 m³ and 216 m³, we can set up the proportion as follows:
1,331 / 216 = (length of the larger solid)³ / (length of the smaller solid)³
Now, solve for the ratio of lengths:
(length of the larger solid) / (length of the smaller solid) = (1,331 / 216)^(1/3)
(length of the larger solid) / (length of the smaller solid) ≈ 2.269
Since length is a linear dimension, we know that the ratio of surface areas for similar solids is the square of the ratio of lengths:
(surface area of the larger solid) / (surface area of the smaller solid) = [(length of the larger solid) / (length of the smaller solid)]²
Given that the surface area of the larger solid is 484 m², we can set up the proportion as follows:
484 / (surface area of the smaller solid) = 2.269²
Now, solve for the surface area of the smaller solid:
(surface area of the smaller solid) ≈ 484 / (2.269²) ≈ 144 m²
Therefore, the surface area of the smaller solid is approximately 144 m².
The correct answer is C. 144m².
Sarah is filling a glass sphere with decorative sand. The radius of the sphere is 2 inches. Which is closest to the minimum amount of sand Sarah needs to completely fill the glass sphere?
1. B
2. A
3. D
4. B
5. C
6. C
7. B
8. C
9. C
10. A
11. C
12. C
13. B
14. D
15. B
16. C
17. B
18. C
19. B
20. C