A 35-kg skier skis directly down a frictionless slope angled at 11° to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. What is Fx (in N) if the magnitude of the skier's velocity is.. constant? ..increasing at a rate of 1.0 m/s^2? ..increasing at a rate of 2.0 m/s^2?

Writing the sum of the forces down the slope....


In the first part, a=0



and solvee for Fx?

.. as for the increasing rate.. is it telling me that the 1.0m/s2 is added to the gravity of 9.8m/s2?

3 answers

  1. this is kinda late answer, but still...

    This works for a = 0

    More complete answer... (a!=0)

    So, for increasing rate of a = 1m/s^2
    This is going in negative direction, so

    And for a = 22/s^2

    Crunch in calculator for Fx in Newtons

  2. Actually, just noticed that was for in -x direction, so change sign on acceleration



  3. ur supposed to multiply the 35sintheta with the acceleration due to gravity (9.8)

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