Calculate the masses of Cr2O3, N2, H20 produced from 10.8 g (NH4)2Cr2O7 [ the 2 belongs to the nh4] in an ammonium dichromate volcano reaction.

I need to know what the balance equation is, and im having a little trouble with it. Pleasee help!

Why did the chemistry teacher bring a clown to the class?

Because he wanted to add some laughs to the chemical equations!

Now, let's tackle the balance equation for the ammonium dichromate volcano reaction:

(NH4)2Cr2O7 → Cr2O3 + N2 + H2O

To balance this equation, we need to ensure that both sides have an equal number of each type of atom.

Let's break it down step by step:

1. Begin by balancing the nitrogen (N) atoms. We have 2 N atoms on the left side and 1 N atom on the right side. To balance the N, we need to put a coefficient of 2 in front of NH4 on the right side:

(NH4)2Cr2O7 → Cr2O3 + N2 + H2O

2(NH4)2Cr2O7 → Cr2O3 + N2 + 4H2O

2. Next, let's balance the hydrogen (H) atoms. We have 8 H atoms on the right side but only 8 H atoms (from the ammonium ion NH4) on the left side. Therefore, we don't need to make any changes here.

2(NH4)2Cr2O7 → Cr2O3 + N2 + 4H2O

3. Finally, we balance the chromium (Cr) and oxygen (O) atoms. We have 2 Cr atoms and 14 O atoms on the left side (from the ammonium dichromate), but only 2 Cr atoms and 10 O atoms (from the chromium oxide and water) on the right side. To balance the Cr and O atoms, we put coefficients of 7 and 6 in front of Cr2O3 and H2O, respectively:

2(NH4)2Cr2O7 → 7Cr2O3 + N2 + 4H2O

And there you have it! The balanced equation for the ammonium dichromate volcano reaction is:

2(NH4)2Cr2O7 → 7Cr2O3 + N2 + 4H2O

Now, let's move on to calculating the masses.

To balance the equation, let's start by writing the formula of ammonium dichromate:

(NH4)2Cr2O7

The elements present in ammonium dichromate are nitrogen (N), hydrogen (H), carbon (C), chromium (Cr), and oxygen (O).

Now, let's balance the equation step-by-step:

1. Start by balancing the chromium (Cr) atoms:
There are two chromium atoms on the left side, so we need to have the same number on the right side. We will place a 2 in front of Cr2O3.

(NH4)2Cr2O7 → Cr2O3 + ...

2. Next, balance the nitrogen (N) atoms:
There are two nitrogen atoms on the left side, so we will need to place a 2 in front of N2.

(NH4)2Cr2O7 → Cr2O3 + 2N2 + ...

3. Now, balance the hydrogen (H) atoms:
There are eight hydrogen atoms on the left side, so we will need to place a 4 in front of NH3.

(NH4)2Cr2O7 → Cr2O3 + 2N2 + 4NH3 + ...

4. Finally, balance the oxygen (O) atoms:
On the left side, there are 7 oxygens from the (NH4)2Cr2O7 compound. To match this, we will need 3 oxygens from Cr2O3 and 1 oxygen from H2O.

(NH4)2Cr2O7 → Cr2O3 + 2N2 + 4NH3 + 3H2O

Now that the equation is balanced, we can determine the masses of Cr2O3, N2, and H2O produced.

To calculate the masses, we need the molar masses of each compound:

- Cr2O3: Cr: 52 g/mol, O: 16 g/mol
- N2: N: 14 g/mol
- H2O: H: 1 g/mol, O: 16 g/mol

To find the masses, we use the given mass of (NH4)2Cr2O7, which is 10.8 g, and convert it to moles. Then, using the balanced equation, we can determine the mole ratio of the compounds produced. Finally, we can convert the moles of each compound to the corresponding mass using their molar masses.

Given: mass of (NH4)2Cr2O7 = 10.8 g

Now, let's calculate the masses of Cr2O3, N2, and H2O.

Molar mass of (NH4)2Cr2O7:
(2 x (NH4)) + (2 x Cr) + (7 x O) = (2 x 18) + (2 x 52) + (7 x 16) = 80 + 104 + 112 = 296 g/mol

Moles of (NH4)2Cr2O7:
moles = mass / molar mass = 10.8 g / 296 g/mol = 0.0365 mol

Using the balanced equation, we can determine the mole ratios:

From the equation: (NH4)2Cr2O7 → Cr2O3 + 2N2 + 4NH3 + 3H2O

For every 1 mole of (NH4)2Cr2O7, we get:
- 1 mole of Cr2O3
- 2 moles of N2
- 4 moles of NH3
- 3 moles of H2O

Therefore, using the mole ratios, we can calculate the masses:

Mass of Cr2O3:
mass = moles x molar mass = 0.0365 mol x (2 x 52 + 3 x 16) g/mol = 0.0365 mol x 152 g/mol = 5.56 g

Mass of N2:
mass = moles x molar mass = 0.0365 mol x (2 x 14) g/mol = 0.0365 mol x 28 g/mol = 1.02 g

Mass of H2O:
mass = moles x molar mass = 0.0365 mol x (3 x 18) g/mol = 0.0365 mol x 54 g/mol = 1.97 g

Therefore, the masses of Cr2O3, N2, and H2O produced from 10.8 g of (NH4)2Cr2O7 are approximately:
- Cr2O3: 5.56 g
- N2: 1.02 g
- H2O: 1.97 g

To determine the balanced equation for the reaction, we first need to break down the reactant, ammonium dichromate, ((NH4)2Cr2O7), into its constituent ions.

The ammonium ion (NH4+) consists of one nitrogen atom (N) and four hydrogen atoms (H). The dichromate ion (Cr2O7^2-) contains two chromium atoms (Cr) and seven oxygen atoms (O).

Now, let's balance the equation step by step:

1. Start with the ammonium ion (NH4+):
(NH4)2Cr2O7 → 2NH4+ + ...

2. Next, balance the dichromate ion (Cr2O7^2-):
(NH4)2Cr2O7 → 2NH4+ + Cr2O7^2-

3. Balance the nitrogen (N) atoms:
(NH4)2Cr2O7 → 2NH4+ + Cr2O7^2- + ...

4. Balance the hydrogen (H) atoms:
(NH4)2Cr2O7 → 2NH4+ + Cr2O7^2- + 4H2O

Now the equation is balanced.

According to the balanced equation, for every mole of ammonium dichromate, we obtain 2 moles of ammonium ions (NH4+), 1 mole of dichromate ions (Cr2O7^2-), and 4 moles of water (H2O).

To calculate the masses of Cr2O3, N2, and H2O produced, we need to use the balanced equation and the molar masses of the compounds involved.

1. Calculate the moles of (NH4)2Cr2O7:
Molar mass of (NH4)2Cr2O7 = (2 * molar mass of NH4) + (2 * molar mass of Cr) + (7 * molar mass of O)

2. Convert grams of (NH4)2Cr2O7 to moles using the molar mass.

3. Use the mole ratios from the balanced equation to calculate the moles of Cr2O3, N2, and H2O produced.

4. Convert moles of Cr2O3, N2, and H2O to grams using their respective molar masses.

By following these steps, you will be able to calculate the masses of Cr2O3, N2, and H2O produced from 10.8 g of (NH4)2Cr2O7 in the ammonium dichromate volcano reaction.

The chemical equation is:

(NH4)2Cr2O7 --> Cr2O3 + N2 + 4H2O
•Find the mass of 1 mole of (NH4)2Cr2O7.
•Divide 10.8g (NH4)2Cr2O7 by the mass of 1 mole to get the number of moles.
•The number of moles of N2 and of Cr2O3 are the same as the number of moles of (NH4)2Cr2O7. The grams of N2 and of Cr2O3 can be found by multiplying each molar mass times the number of moles.
•The number of moles of H2O is 4 times the number of moles of the other compounds. The number of grams of H2O is the number of moles times its molar mass.