A5-digit number has 7 in its place The digit in once place is 5 less than its digits at tens place The hundreds place digit is 4 times the digit at once place The digit at thousands place is the same as at hundreds place sum of all the digits is 33 write the number in standard form.
That is one of the longest run-on sentences I have ever seen. Is the . key stuck on your keyboard?
"A5-digit number has 7 in its place" ?????
looks like a typo, .....
let the number be abcde
"The hundreds place digit is 4 times the digit at once place" , once ??, you mean one's ?
ab4d1 or ab8d2
"The digit in once place is 5 less than its digits at tens place"
ab461 or ab472
"The digit at thousands place is the same as at hundreds"
a4461 or a4472
"sum of all the digits is 33 "
a+4+4+6+1 = 33
a = 18 , which is not possible
or
a+4+4+7+2 = 33
a = 16 , also not possible
your problem cannot work.
To find the 5-digit number given the conditions provided, we can break down the information step by step.
Step 1: The digit in the ones place is 5 less than the digit in the tens place.
Let's call the digit in the tens place 'x'. Therefore, the digit in the ones place would be 'x - 5'.
Step 2: The hundreds place digit is 4 times the digit at the ones place.
Since the digit at the ones place is 'x - 5', the digit at the hundreds place would be '4 * (x - 5)'.
Step 3: The digit at the thousands place is the same as the digit at the hundreds place.
Therefore, the digit at the thousands place is also '4 * (x - 5)'.
Step 4: The sum of all the digits is 33.
To find the value of 'x', we can sum up all the digits and set it equal to 33:
x + (x - 5) + 4 * (x - 5) + 4 * (x - 5) + (x - 5) = 33
Now, let's solve this equation to find the value of 'x'.
x + x - 5 + 4x - 20 + 4x - 20 + x - 5 = 33
11x - 55 = 33
11x = 88
x = 8
Now that we have found the value of 'x' as 8, we can substitute it back into the previous steps to find the digits at each place.
Step 1: The digit in the ones place is 5 less than the digit in the tens place.
The digit in the ones place = 8 - 5 = 3
Step 2: The hundreds place digit is 4 times the digit at the ones place.
The digit in the hundreds place = 4 * 3 = 12
Step 3: The digit at the thousands place is the same as the digit at the hundreds place.
The digit in the thousands place = 12
Finally, let's write the number in standard form using the information we have:
The number is: 12,832