The bases are right trapezoids with bases of lengths 8 and 14 perpendicular to one side of length 18; height = 11.
so, the area is two trapezoids and four rectangles
2[(8+14)/2 * 18] + 8*11 + 14*11 + 18*11 + 11√(6^2+18^2)
1. Find the surface area for the given circle. A.) 564 in² B.) 664 in² C.) 1,120 in² D.) 1,080 in² 2. Find the lateral area for the given prism. A.) 1,092 cm² B.) 998 cm² C.) 1,272 cm² D.) 870 cm² 3. Find the surface area for the given cylinder.
In a right prism whose bases are regular hexagons what is the measure of the dihedral angle between adjacent lateral faces?
1. which solid has two bases that are triangles and three lateral surfaces that are rectangles a. triangular pyramid b. rectangular prism c. triangular prism *** d. rectangular pyramid 2. a solid with two parallel and congruent bases cannot be which of the
The length of a solid prism is 10cm. It's cross section is an equilateral triangle of sides 6cm. Find the total surface area of the prism
check my answers pls 1. which solid has two bases that are triangles and three lateral surfaces that are rectangles a. triangular pyramid b. rectangular prism c. triangular prism *** d. rectangular pyramid 2. a solid with two parallel and congruent bases
A rectangular prism has a square base with area 9 m2. The surface area of the prism is 78 m2. What are the dimensions of the prism?
The altitude of the regular quadrilateral prism is h=13 cm and lateral area is AL = 624 cm2. Find: 1) The Surface Area of the prism; 2) The Volume of the prism. Answer:
Matthew is constructing a rectangular prism with a volume of 729 cubic inches. The prism will have the least possible surface area. a) describe the prism and what will be its dimensions b) what will be its surface area
Find the surface area of the triangular prism. A) 2,216 B) 2,352*** C) 2,384 D) 5,376 (*** means my answer)
What is the lateral surface area of the prism? Rectangular prism Length: 17.2 Width: 3 Height: 5.5 283.8 m^2 292.4 m^2 325.4 m^2 407 m^2 I already found the surface area (325.4 m^2) and I'm using the formula for lateral surface area 2lh + 2wh... but I keep
You can ask a new question or browse existing questions.