For the function f(x) = x^2  4x +5, x>= 2, which is equal to d/dx (f1 this is the inverse)(x)) ?
1/(2y4) where x and y are related by the equation (satisfy the equation) x=y^24y+5 x>= 1
2y4 where x and y are related by the equation y= = x^2  4x +5, x>= 2
1/2x4 for x>= 1
1/2x4 for x>= 2
1/2y4 where x and y are related by the equation y= = x^2  4x +5, x>= 2
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3 answers

Answer is 1/(2y4) where x and y are related by the equation (satisfy the equation) x=y^24y+5 x>= 1
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answered by Thomas 
inverse of x^2  4x +5 is 2±sqrt(x1) and the derivative of that is (2x4) but I don't know how to get the x>= 1 or x>= 2
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answered by Thomas 
The inverse function is x=y^24y+5
And the domain start from 1 to infinity to make onetoone function. So, you get y' of inverse function = 1/(2y4) where [1,infinity). 👍
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answered by Paulie
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