Write the equation of a sine wave (also called sine curve) given:
amplitude = 2
period = pi/2
phase shift = pi/8
vertical shift = 1
amplitude = 4
period = 3
phase shift = 2
vertical shift = -1
amplitude = 4
period = pi
phase shift = -(pi/3)
vertical shift = 0
1. y = 2(sin(4x - pi/8)) + 1
2. y = 4(sin((2pi/3)x - 2)) - 1
3. y = 4(sin(2x + pi/3)
I disagree with your phase shift
y = a sin k(x - d) + c
the phase shift is d. Notice that the period indicator k is factored out
In your answer we have ... sin(4x - π/8) ...
or ... sin 4(x - π/32)...
So the phase shift of your equation would be π/32
1. y = 2 sin 4(x - π/8) + 1 or y = 2 sin (4x -
2. y = 4 sin (2π/3)(x - 2)) - 1 or y = 4 sin (2π/3)x - 4π/3) - 1
3. y = 4 sin 2(x + π/3)
first answer line should be
1. y = 2 sin 4(x - π/8) + 1 or y = 2 sin (4x - π/2) + 1
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