For questions 5–7, find the solution to the system of equations by using either graphing or substitution
5. y = 6 – x and y = x – 2 (1 point)
(2, 4)***
(–4, 2)
(4, 2)
no solutions
6. y = 2x – 1 and y = x + 3 (1 point)
(4, 7)
(7, 4)
(–7, –4)***
infinite solutions
7. y = 4x and y + x = 5 (1 point)
(–4, 1)
(1, 4) ***
(–3, 2)
(2, 3)
am i right?
c
a
b
d
solving systems of equations by graphing
All I did was to sub in your choice into each of the equations.
#7 is correct, the other two are not
#5
since both say y = ...
we can substitute:
x-2 = 6-x
2x = 8
x = 4
back in the first:
y = 6-4 = 2 , so (4,2)
#6 , same way ...
2x-1 = x+3
x = 4
then y = 8-1 = 7
solution: (4,7)
LOL Unknown is 100% correct
LOL
Unknown is correct 💯
thx
Actually for the fellas unknown is right for a different test because I got a 100 so you got the wrong test help is here
I apologize if there was any confusion. As an AI language model, I can provide guidance, but ultimately the accuracy of the answers depends on the specific equations given. If you are confident in your answers based on your test, then that is great. It's always important to double-check and verify the solutions with your teacher or textbook to ensure correctness.
For question 5, the equations are y = 6 - x and y = x - 2. To find the solution, you can use either graphing or substitution method.
Let's solve it using substitution:
1. Start with the first equation, y = 6 - x.
2. Substitute this expression for y in the second equation.
x - 2 = 6 - x
3. Add x to both sides of the equation.
x + x - 2 = 6
2x - 2 = 6
4. Add 2 to both sides of the equation.
2x = 8
5. Divide both sides of the equation by 2 to solve for x.
x = 4
6. Substitute this value of x back into any of the original equations to solve for y.
y = 6 - 4
y = 2
Therefore, the solution to the system of equations is (4, 2), so your answer is correct.
For question 6, the equations are y = 2x - 1 and y = x + 3. Let's solve it using substitution:
1. Start with the first equation, y = 2x - 1.
2. Substitute this expression for y in the second equation.
2x - 1 = x + 3
3. Subtract x from both sides of the equation.
2x - x - 1 = 3
x - 1 = 3
4. Add 1 to both sides of the equation.
x - 1 + 1 = 3 + 1
x = 4
5. Substitute this value of x back into any of the original equations to solve for y.
y = 2(4) - 1
y = 8 - 1
y = 7
Therefore, the solution to the system of equations is (4, 7), so your answer is incorrect.
For question 7, the equations are y = 4x and y + x = 5. Let's solve it using substitution:
1. Start with the second equation, y + x = 5.
2. Solve this equation for y by subtracting x from both sides.
y = 5 - x
3. Substitute this expression for y in the first equation.
5 - x = 4x
4. Add x to both sides of the equation.
5 = 5x
5. Divide both sides of the equation by 5 to solve for x.
x = 1
6. Substitute this value of x back into any of the original equations to solve for y.
y = 4(1)
y = 4
Therefore, the solution to the system of equations is (1, 4), so your answer is correct for question 7.
Unknown is wrong i got 0/4
1.D. Inconsistent
2.C. Infinite
3.D. (4,-1)
4.B. Exactly to solutions