Rod a is twice as long as rod b, rod c is 1/12m shorter than rod b. If rod c is 1/6m long, find the total length of Rod a and Rod b
I thought it would be 2x+(x+1/12)+1/6
B = A/2
B = C + 1/12 = 1/6 + 1/12 = 2/12 + 1/12 = ?
Put answer to second equation into the first to find A, then add the two.
So A= 1/4
B= 1/8
C= 1/6 right?
The question was to find the length of A and B together.
a+b = 2b+b = 3b = 3(c + 1/12) = 3(1/6 + 1/12) = 3(3/12) = 3(1/4) = 3/4
You rock! Thanks!!
To find the total length of Rod a and Rod b, let's assign variables to each rod:
Let's say the length of Rod b is x meters.
According to the information given:
- Rod a is twice as long as Rod b, so the length of Rod a would be 2x meters.
- Rod c is 1/12 meter shorter than Rod b, so the length of Rod c would be (x - 1/12) meters.
Now, we also know that the length of Rod c is 1/6 meter (given in the question). So we can set up an equation to solve for x.
(x - 1/12) = 1/6
To solve this equation, we can first get rid of the fractions by multiplying both sides of the equation by 12 (the least common multiple of 12 and 6):
12 * (x - 1/12) = 12 * (1/6)
After simplifying, the equation becomes:
12x - 1 = 2
Adding 1 to both sides of the equation:
12x = 3
Finally, divide both sides of the equation by 12:
x = 3/12
So, the length of Rod b is 1/4 meter.
Now, we can find the length of Rod a by multiplying the length of Rod b by 2:
Length of Rod a = 2 * (1/4) = 1/2 meter.
To find the total length of Rod a and Rod b, simply add their lengths:
Total length = Length of Rod a + Length of Rod b
= 1/2 + 1/4
= 2/4 + 1/4
= 3/4
Therefore, the total length of Rod a and Rod b is 3/4 meter.