# An isosceles, obtuse triangle has one angle with a degree measure that is 50% larger than the measure of a right angle. What is the measure, in degrees, of one of the two smallest angles in the triangle? Express your answer as a decimal to the nearest tenth.

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1. 50% larger than a right angle would be (90+45)° or 135°
That leaves 45° for the two equal angles, making each one 22.5°

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2. An angle with measure $50\%$ larger than the measure of a right angle has measure $\frac{3}{2}\cdot 90^{\circ}=135^{\circ}$.

Thus the other two angles have a combined measure of $45^{\circ}$ Each one has a measure of

$$\frac{45^{\circ}}{2}=\boxed{22.5^{\circ}}$$

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3. STOP CHEATING

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4. It is not cheat, it is not aops problem

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