The two insulated beakers contain equal amounts of identical liquids. The temperature of Beaker A is 80°C. The temperature of Beaker B is 50°C. A copper rod connects the beakers. The system is then left alone for several hours. What would you expect to find when the system is examined after this time?
A. The temperature of Beaker A would be 50°C and the temperature of Beaker B would be 80°C.
B. The temperatures of the two beakers would be unchanged.
C. Both of the beakers would be at a temperature of 50°C.
D. Both of the beakers would be at a temperature of 65°C. i think answer is a
stupids
whoops didn't mean to pt that
To determine the expected outcome, we need to understand the principles of heat transfer and thermal equilibrium.
The heat will flow from the hotter object (Beaker A) to the colder object (Beaker B) until they reach thermal equilibrium, where their temperatures are the same. This process is called thermal conduction.
The copper rod acts as a conductor, allowing the heat to flow from Beaker A to Beaker B. Copper is a good conductor of heat, meaning it transfers heat efficiently.
Therefore, after several hours, we would expect the temperature of Beaker A to decrease and the temperature of Beaker B to increase. However, they will both approach the same temperature.
Hence, the correct answer is C. Both of the beakers would be at a temperature of 50°C.