calculate the mass of silver deposited when a current of 2.6a is passed through a solution of a silver salt for 70mins ag=108,1 faraday 96500

Convert 70 min to seconds.

coulombs = C = Amps x seconds. C = approx 1E4 C but you need to do it more accurately than that.
Then 96,500 C will deposit 108.1 g (are you sure about the atomic mass Ag???. More like 107.9 I thought). So
108.1 x (1E4/96,500) = ? g Ag deposited.

12.22

calculate the Mass of silver deposited when a current of 2.6A is passed through a solution of a silver salt for 70 minutes (Ag =108 1 Faraday=96500)

Calculated the mass of silver deposited when a current of 2.6A is passed through a solution of a silver for 70minutes (Ag=108;1 Faraday=96500c)

calculate the mass of silver deposited when a current of 2.6A is passed through solution of a silver salt for 70 minutes(Ag=108,IF=96500 c)

You will cross multiply

M=Q * m.m / f * c

M=10920 * 108 / 96500 * 1
M= 12.22g

How will you calculate it after changing the minutes to second and finding your Coulombs which is current × time

in this question Q=it. i=2.6A t=70min. Q=2.6*70*60=10920C

108g yield 96500F
Xg will yield 10920C
cross multiply you will have
10920*108/96500=12.22g

To calculate the mass of silver deposited, we need to use the formula:

Mass of silver = (Current × Time × Atomic mass of silver) / (Faraday's constant × Valency of silver)

Given:
Current (I) = 2.6 A
Time (t) = 70 mins = 70 × 60 seconds = 4200 seconds
Atomic mass of silver (Ag) = 108.1 g/mol
Faraday's constant (F) = 96500 C/mol
Valency of silver = 1

Substituting the values into the formula, we have:

Mass of silver = (2.6 A × 4200 s × 108.1 g/mol) / (96500 C/mol × 1)

Now let's calculate it step by step:

1. Multiply the current, time, and atomic mass of silver:
(2.6 A × 4200 s × 108.1 g/mol) = 1141140.0 g·s/mol

2. Divide the result by the product of Faraday's constant and the valency of silver:
1141140.0 g·s/mol / (96500 C/mol × 1) = 11.83 g

Therefore, the mass of silver deposited when a current of 2.6 A is passed through the solution for 70 minutes is approximately 11.83 grams.