Your car rides on springs, so it will have a natural frequency of oscillation. (Figure 1) shows data for the amplitude of motion of a car driven at different frequencies. The car is driven at 24mph over a washboard road with bumps spaced 12 feet apart; the resulting ride is quite bouncy. Determine the frequency of the oscillation, caused by the bumps. 1 mile is 5280 feet.
The graph shows a curve that extends over 6hz. It has a peak.
A 1000-kg car traveling on a horizontal road at 24m/s sees a cow 50m ahead. Will the car be able to stop before reaching the cow? The maximum coefficient of friction between the car tires and the road is 0.60. Ignore the driver’s reaction time and assume that g=10m/s^2
First, find the frequency by unit conversions.
frequency = (24 miles/1 hour)(5280 feet/1 mile)(1 hour/3600 seconds)(1/12 feet) = 2.933 Hz
Then, read the graph to see if you need to speed up or slow down. Speeding up moves you towards 6 Hz. You want somewhere where the amplitude is low. Move just one Hz to either side when reading the graph. Don't try to make the car slow to zero.
What is the frequency of a rides oscillation
Well, it looks like your car is really getting into the groove on that washboard road! That peak on the graph represents the natural frequency of oscillation caused by the bumps. To determine the frequency, we need to know the exact location of the peak. Without that information, it's like trying to find a clown's nose in a haystack without a clown in sight. So, if you can provide the specific value for the peak frequency, I'll be happy to calculate it for you!
To determine the frequency of the oscillation caused by the bumps, we need to analyze the given information and the graph.
From the question, we know that the car is driven at 24 mph (miles per hour) over a washboard road with bumps spaced 12 feet apart. We also know that 1 mile is equal to 5280 feet.
To find the frequency, we need to convert the car's speed from mph to feet per hour. We can do this by multiplying the given speed (24 mph) by the conversion factor of 5280 feet/mile.
24 mph * 5280 feet/mile = 126,720 feet/hour
Now, let's consider the bumps spaced 12 feet apart. This spacing represents the wavelength of the oscillation. We can use the formula for frequency to find the oscillation frequency (f):
Frequency (f) = Speed (v) / Wavelength (λ)
Substituting the values, we get:
f = 126,720 feet/hour / 12 feet
Simplifying:
f ≈ 10,560
So, the frequency of the oscillation caused by the bumps is approximately 10,560 Hz.