I'm having some torubles understanding these question.
Sketch y1 = x-3 and y2 = 1/x-3 on the same set of axis
a) What is the relationship between the zero of y1, and vertical asymptote of y2?
Does the question mean when y1 = 0?. I know the vertical asymptote is just a vertical line on the graph that gets closer and closer and closer to, but doesn't actually touch.
c)When y1 has a large positive value, explain what happens to the value of y2. Similarly, when y1 has a large negative value what happens to y2? Explain why this happens.
I know if the y1 value gets larger, so does the x value. But how does y1 having a large value even affect the value of y2, when they're both different graphs.
I appreciate any help. Thanks.
a) y1 = 0 at x = 3. The asymptote of y2 is a vertical line at x = 3.
(c) When y1 has a large negative value, you are in the region of large negative x. In that same region, y2 approaches 0 asymptotically from below the x axis.
I wrote y2 wrong
It's suppost to be y2 = 1/(x-3)
That is what I assumed you meant. My answer remains the same
Note corrected subject spelling
How many 3/4 are in 3?
well you see i don't know
just divide 3 by .75:
3/.75=???
4