A fighter pilot is exposed to an acceleration of 3g in the horizontal direction during takeoff. Knowing that 1g=9.8 m/s2 and that the mass of the fighter pilot is 63.6 kg, what force (in Newtons) does the fighter pilot experience in the horizontal direction? This is the force that she feels "pressing her into the back of the seat.”

Well, well, well, looks like the fighter pilot is in for a wild ride! To figure out the force pressing her into the back of the seat, we need to multiply the acceleration by her mass. Using the formula, Force = mass × acceleration, we get Force = 63.6 kg × 3g × 9.8 m/s². But hold on, we need to convert that 3g to meters per second squared first. Since 1g = 9.8 m/s², 3g will be 3 × 9.8 m/s². Now let me grab my calculator... *bzzzt* Oops, seems like my calculator couldn't handle the gravitational force of that acceleration! Anyways, just multiply the mass by the acceleration to get the force in Newtons. Good luck, pilot! And remember, no funny business in the cockpit!

To calculate the force experienced by the fighter pilot in the horizontal direction, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).

Given:
Acceleration = 3g
1g = 9.8 m/s^2
Mass (m) = 63.6 kg

We need to convert the acceleration from g to m/s^2:

Acceleration = 3g
Acceleration = 3 x 9.8 m/s^2
Acceleration = 29.4 m/s^2

Now, we can calculate the force:

Force (F) = mass (m) x acceleration (a)
F = 63.6 kg x 29.4 m/s^2
F ≈ 1869.84 N

Therefore, the fighter pilot experiences a force of approximately 1869.84 Newtons in the horizontal direction, which feels like being "pressed into the back of the seat".

To calculate the force experienced by the fighter pilot during takeoff, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

Given:
Acceleration, a = 3g (where 1g = 9.8 m/s²)
Mass, m = 63.6 kg

First, we need to convert the acceleration from g to m/s²:
Acceleration in m/s² = (3g) * (9.8 m/s²)

Substituting the given values:
Acceleration in m/s² = (3 * 9.8 m/s²)

Now we can calculate the force:
Force (F) = m * a

Substituting the given values:
Force (F) = 63.6 kg * (3 * 9.8 m/s²)

Multiply the values:
Force (F) = 63.6 kg * 29.4 m/s²

Calculating further:
Force (F) = 1870.64 N

Therefore, the force experienced by the fighter pilot due to the acceleration of 3g in the horizontal direction during takeoff is approximately 1870.64 Newtons.

F = M * 3g = 63.6kg * 3*9.8N/kg =

1869.84