A person in a kayak starts paddling, and it accelerates from 0 to 0.63 m/s in a distance of 0.45 m. If the combined mass of the person and the kayak is 69 kg, what is the magnitude of the net force acting on the kayak?

V^2 = Vo^2 + 2a*d

a = (V^2-Vo^2)/2d

V = 0.63 m/s
Vo = 0
d = 0.45 m.
Solve for a.

F = M*a
M = 69 kg
Solve for F.

Well, isn't that a slippery situation! Let's calculate the magnitude of the net force on the kayak.

To determine the net force, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration (F = m*a).

Given that the mass of the person and the kayak is 69 kg, and the acceleration is (0.63 m/s) / (0.45 m), we can plug these values into the equation to find the net force:

F = 69 kg * (0.63 m/s / 0.45 m)

Now, let me grab my calculator... *sounds of a calculator clacking*

Voila! The magnitude of the net force acting on the kayak is approximately 96.6 newtons. That's quite a pull, huh?

To find the magnitude of the net force acting on the kayak, we need to use Newton's second law of motion, which states that the net force is equal to the mass of an object multiplied by its acceleration.

Given:
Initial velocity, u = 0 m/s
Final velocity, v = 0.63 m/s
Distance traveled, s = 0.45 m
Mass of the person and kayak, m = 69 kg

First, we can find the acceleration using the equation:

v^2 = u^2 + 2as

Plugging in the values:

0.63^2 = 0^2 + 2a(0.45)

0.3969 = 0.9a

Now, solve for the acceleration, a:

a = 0.3969 / 0.9
a ≈ 0.441 m/s^2

Now, we can find the net force using the equation:

F = ma

Plugging in the values:

F = 69 kg * 0.441 m/s^2
F ≈ 30.429 N

Therefore, the magnitude of the net force acting on the kayak is approximately 30.429 Newtons.

To determine the magnitude of the net force acting on the kayak, we can use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). Mathematically, this can be represented as:

F_net = m * a

In this case, the mass of the person and the kayak is given as 69 kg, and the kayak accelerates from 0 to 0.63 m/s in a distance of 0.45 m. To find the acceleration, we can use the kinematic equation:

v^2 = u^2 + 2a * s

Where:
v is the final velocity (0.63 m/s),
u is the initial velocity (0 m/s),
a is the acceleration (unknown),
s is the displacement (0.45 m).

Rearranging the equation to solve for acceleration:

a = (v^2 - u^2) / (2 * s)

Plugging in the given values:

a = (0.63^2 - 0^2) / (2 * 0.45)
= 0.1989 / 0.9
= 0.221 m/s^2

Now that we have the acceleration, we can substitute it back into Newton's second law:

F_net = m * a
= 69 kg * 0.221 m/s^2
= 15.249 kg*m/s^2

The unit of force is called the Newton (N), so the magnitude of the net force acting on the kayak is approximately 15.249 N.