A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. What is the magnitude of the current flowing through the first device?

A. 10 A
B. 3.33 A
C. 8 A
D. 13.32 A

im guessing b?

Your are correct!

current for 40 volts across 12 ohms:
40V/12 ohms=3.33 smps

oops...

I meant amps.

thanks ;D

To find the magnitude of the current flowing through the first device, you can use Ohm's Law. Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R), or I = V/R.

In this case, the resistance of the first device is given as 12 ohms and the voltage developed by the generator is 40 V. Plugging these values into the formula, you get:

I = V/R
I = 40 V / 12 ohms

Calculating this, you get:

I ≈ 3.33 A

So, the correct answer is B. 3.33 A.