Find two numbers with a sum of -8 and a difference of 4. Let x be the greater number and y be the lesser number.
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x= -2
y= -6
Thank you!
Eq1: x + y = -8
Eq2: x - y = 4
Sum: 2x = -4
X = -2
In Eq1, replace x with -2:
-2 + y = -8
Y = -6.
To find two numbers with a sum of -8 and a difference of 4, let's first set up two equations based on the given information.
Let x be the greater number and y be the lesser number.
Equation 1: x + y = -8 (since the sum of the two numbers is -8)
Equation 2: x - y = 4 (since the difference between the two numbers is 4)
Now, we can solve these equations using the method of substitution or elimination to find the values of x and y.
Method 1: Substitution
From Equation 2, isolate x in terms of y:
x = y + 4
Then substitute this value of x into Equation 1:
(y + 4) + y = -8
2y + 4 = -8
2y = -12
y = -6
Now substitute the value of y back into Equation 2 to find x:
x - (-6) = 4
x + 6 = 4
x = -2
Therefore, the two numbers are x = -2 and y = -6.
Method 2: Elimination
Multiply Equation 1 by -1 to change the sign of the sum:
-x - y = 8
Now add Equation 1 and Equation 2 together to eliminate x:
(-x - y) + (x - y) = 8 + 4
-2y = 12
y = -6
Substitute the value of y back into Equation 1 to find x:
x + (-6) = -8
x = -8 + 6
x = -2
So, the two numbers are x = -2 and y = -6.
Therefore, the two numbers with a sum of -8 and a difference of 4 are -2 and -6, with x = -2 being the greater number and y = -6 being the lesser number.