If 0.130 g of p-aminophenol is allowed to react with excess acetic anhydridre , what is the theoretical yield of acetaminophen in moles ?In grams?
mols p-a = grams/molar mass
mols aceta = mols p-a
g aceta = mols aceta x molar mass aceta
That is the theoretical yield.
To determine the theoretical yield of acetaminophen (C8H9NO2), we need to use the equation of the reaction and the molar masses of p-aminophenol (C6H7NO) and acetaminophen.
The balanced chemical equation for the reaction is:
C6H7NO + (C2H3O)2O → C8H9NO2 + CH3COOH
First, we need to convert the mass of p-aminophenol (0.130 g) to moles. To do this, we'll need to know the molar mass of p-aminophenol:
C: 12.011 g/mol
H: 1.008 g/mol
N: 14.007 g/mol
O: 15.999 g/mol
Molar mass of p-aminophenol: (6 × 12.011 g/mol) + (7 × 1.008 g/mol) + 14.007 g/mol + 15.999 g/mol = 109.126 g/mol
Now, we can calculate the moles of p-aminophenol:
moles = mass / molar mass = 0.130 g / 109.126 g/mol = 0.00119 mol
From the balanced chemical equation, we can see that the stoichiometric ratio between p-aminophenol and acetaminophen is 1:1. This means that they react in a 1:1 molar ratio.
Therefore, the theoretical yield of acetaminophen in moles is also 0.00119 mol.
To calculate the theoretical yield of acetaminophen in grams, we need to know its molar mass:
C: 12.011 g/mol
H: 1.008 g/mol
N: 14.007 g/mol
O: 15.999 g/mol
Molar mass of acetaminophen: (8 × 12.011 g/mol) + (9 × 1.008 g/mol) + 14.007 g/mol + (2 × 15.999 g/mol) = 151.163 g/mol
Now, we can convert the moles of acetaminophen to grams:
mass = moles × molar mass = 0.00119 mol × 151.163 g/mol ≈ 0.180 g
Therefore, the theoretical yield of acetaminophen is approximately 0.180 grams.