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A 0.60 kg object with an initial velocity of 3.0 m/s in the positive x direction is acted on by a force in the direction of motion. The force does +2.5 J of work. What is the final velocity of the object?

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2 answers
  1. KE = KE1 + KE2 = 0.5*M*V^2 + KE2 =
    0.5*0.6*3^2 + 2.5 = 5.2 J.

    KE = 0.5*0.6*V^2 = 5.2
    V^2 = 17.33
    V = 4.16 m/s.

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  2. A 0.60 kg Volleyball is moving with a intial velocity of 8 m/s and final velocity of 16 m/s. What is the total work done of this object? *

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