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3 kg object is fastened to a light spring with the intervening cord passing over a pulley. The pulley is frictionless and it's inertia may been neglected. The object is released from rest when the spring is unstretched. If the object drops 10 cm before stopping find the spring constant of the spring and the speed of the object when it is 5 cm below with starting point.

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2 answers
  1. The object did not oscillate? Hmmmm.
    Ok, if it came to rest at 10 cm, then
    f=kx
    k=3g/.1= 30*9.8 N/m

    now, the speed half way down.

    gPE lost=KE+spring energy stored
    mgh=1/2 mv^2+1/2 k x^2
    .05g=1/2 v^2 + 1/2 30*9,8*.05^2
    solve for v

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    bobpursley
  2. The spring force should be 588 N/m and velocity 0.700 m/s

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