Determine the mass (in grams) of a 1% solution of Manganese(II) Sulfate that will contain 0.0403 grams.

if one percent is .0403 grams, then 100 percent should be 4.03 grams

.000403

To determine the mass of the 1% solution of Manganese(II) Sulfate, we need to use the formula:

Mass of solute = (percent concentration / 100) * Mass of solution

Given:
Percent concentration = 1%
Mass of solute = 0.0403 grams

Let's calculate the mass of the solution:

Mass of solution = Mass of solute / (percent concentration / 100)
= 0.0403 grams / (1 / 100)
= 0.0403 grams / 0.01
= 4.03 grams

Therefore, the mass of the 1% solution of Manganese(II) Sulfate is 4.03 grams.

To determine the mass of a 1% solution of Manganese(II) Sulfate that will contain 0.0403 grams, we need to follow these steps:

Step 1: Understand the question.
The question asks for the mass of a 1% solution of Manganese(II) Sulfate that will contain 0.0403 grams. A 1% solution means that 1 gram of the solute is dissolved in 100 grams of the solvent. In this case, the solute is Manganese(II) Sulfate.

Step 2: Calculate the mass of the solute required.
Since a 1% solution means 1 gram of solute is dissolved in 100 grams of solvent, we can set up a proportion to find the mass of Manganese(II) Sulfate required:

1 gram Manganese(II) Sulfate / 100 grams solution = x grams Manganese(II) Sulfate / 0.0403 grams

Solving this proportion, we get:
x grams Manganese(II) Sulfate = (1 gram Manganese(II) Sulfate / 100 grams solution) * 0.0403 grams

x = (0.01 g/1 g) * 0.0403 g

Step 3: Perform the calculation.
x = 0.000403 g

Therefore, the mass of Manganese(II) Sulfate required is 0.000403 grams.