phoebe physics pulls a wagon with a force of 80 N.
a) what is the net force of friction between the wagon and the ground is 12 N.
b) if she uses 80 N to pull the wagon through a med puddle, and the net force on the wagon is 38 N, what friction force asts on the wagon?
68N
42N
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a) Well, it looks like the wagon is feeling a little bit of resistance from the ground. With a net force of 80 N pulling forward and a friction force of 12 N pushing back, the net force would be 80 N - 12 N, which equals 68 N. So the net force of the wagon is 68 N.
b) Ah, the joys of pulling wagons through puddles! If Phoebe is using her full strength of 80 N to overcome the resistance of the puddle, but the net force on the wagon is only 38 N, we can deduce that the friction force acting on the wagon is 80 N - 38 N, which equals 42 N. So the friction force on the wagon would be 42 N.
Remember, it's important to use caution while pulling wagons through puddles - you never know when they might put up a resistance!
a) To find the net force, subtract the force of friction from the applied force:
Net force = Applied force - Force of friction
Net force = 80 N - 12 N
Net force = 68 N
Therefore, the net force is 68 N.
b) The net force can be calculated by subtracting the force of friction from the applied force:
Net force = Applied force - Force of friction
Net force = 80 N - Force of friction
Given that the net force is 38 N, we can calculate the force of friction:
38 N = 80 N - Force of friction
To isolate the force of friction, we rearrange the equation:
Force of friction = 80 N - 38 N
Force of friction = 42 N
Therefore, the friction force acting on the wagon is 42 N.
To determine the friction force acting on the wagon in both scenarios, we need to apply Newton's second law of motion, which states that the net force on an object is equal to the product of its mass and acceleration (F = ma). In both cases, the wagon is not accelerating, so the net force on the wagon is equal to zero (since acceleration is zero).
a) To calculate the friction force when the net force is 12 N, we know that the force exerted by Phoebe on the wagon is 80 N. Since the net force is the force applied minus the force of friction, we can write the equation:
Net force = Force applied - Force of friction
0 N = 80 N - Force of friction
To solve for the force of friction, we rearrange the equation:
Force of friction = Force applied - Net force
Force of friction = 80 N - 0 N
Force of friction = 80 N
Therefore, the friction force between the wagon and the ground is 80 N.
b) In this scenario, the net force on the wagon is 38 N, and the force applied by Phoebe is 80 N. Again, we can set up the equation:
Net force = Force applied - Force of friction
38 N = 80 N - Force of friction
To find the force of friction, we rearrange the equation:
Force of friction = Force applied - Net force
Force of friction = 80 N - 38 N
Force of friction = 42 N
Therefore, the friction force acting on the wagon is 42 N.