The linear impulse delivered by the hit of a boxer is 97.7 N·s during the 0.368 s of contact.

What is the magnitude of the average force exerted on the glove by the other boxer?
Answer in units of N.

average force = change of momentum/time

instantaneous force if m is constant = m A

so

average force = 97.7 / .368 Newtons

Well, with all that contact time and linear impulse, it sounds like those boxers really know how to make an impression! Now, to find the magnitude of the average force exerted on the glove by the other boxer, we can use the formula:

Average force = Impulse / Contact time

Plugging in the values, we get:

Average force = 97.7 N·s / 0.368 s

Calculating that, we find that the magnitude of the average force exerted on the glove is approximately 265.71 N.

So, it seems that the other boxer really packed a punch!

The magnitude of the average force exerted on the glove by the other boxer can be calculated using the equation:

Average force = Change in momentum / Time

First, let's determine the change in momentum:

Change in momentum = Linear impulse = 97.7 N·s

Next, let's calculate the average force:

Average force = 97.7 N·s / 0.368 s

Average force ≈ 265.76 N

Therefore, the magnitude of the average force exerted on the glove by the other boxer is approximately 265.76 N.

To find the magnitude of the average force exerted on the glove by the other boxer, we can use the formula for impulse:

Impulse = force × time

We are given the impulse (97.7 N·s) and the time of contact (0.368 s). Rearranging the equation, we have:

Force = Impulse / time

Plugging in the given values, we can calculate the force exerted on the glove:

Force = 97.7 N·s / 0.368 s
Force ≈ 265.76 N

Therefore, the magnitude of the average force exerted on the glove by the other boxer is approximately 265.76 N.