A taxi company charges passengers $1.00 for a ride, and an additional $0.30 for each mile traveled. The function rule C = 0.30m + 1.00 describes the relationship between the number of miles m and the total cost of the ride c. If the taxi company will only go a maximum of 40 miles, what is a reasonable graph of the function rule?

pls help? don't know!

CAN you say the answer? I'm kinda stuck...

thanks i got a 5/5 @lilly

what is the answerrrrr

A taxi company charges passengers $2.00 for a ride, no matter how long the ride is, and an additional $0.20 for each mile traveled. The rule c = 0.20m + 2.00 describes the relationship between the number of miles m and the total cost of the ride c.

a. What is the charge for a 1-mile ride?
b. What is the charge for a 2.7-mile ride?




$0.20; $0.54



$2.00; $2.20



$0.20; $5.60



$2.20; $2.54

Checked my answers with Lilly and 100% correct! Thanks.

To graph the function rule C = 0.30m + 1.00, you will need to plot points on a coordinate plane. Each point will represent the number of miles traveled (m) and the corresponding total cost of the ride (C).

Since the taxi company will only go a maximum of 40 miles, you can choose different values for m, such as 10, 20, 30, and 40. Then you can calculate the corresponding values for C using the function rule.

For example:
- When m = 10, C = 0.30(10) + 1.00 = $4.00
- When m = 20, C = 0.30(20) + 1.00 = $7.00
- When m = 30, C = 0.30(30) + 1.00 = $10.00
- When m = 40, C = 0.30(40) + 1.00 = $13.00

Plot these points on the coordinate plane, where the x-axis represents the number of miles (m) and the y-axis represents the total cost (C). Connect the points with a straight line to get the graph.

Based on the calculations, the points to plot are:
(10, 4), (20, 7), (30, 10), (40, 13)

The reasonable graph of the function rule C = 0.30m + 1.00 would be a straight line that starts at (0,1) and goes through the plotted points, extending up to (40,13).

the answers to the 5 question test "graphing a function rule" is

C
true
D
C
A

nevermind, i figured it out. sorry for the useless post ):

Do your own work dude.