Two 4.6 g bullets are fired with speeds of 36.9

m/s and 74.8 m/s, respectively.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
b) What is the kinetic energy of the second
bullet?
Answer in units of J.

I got part A), which is 3.131703J but i cant get part B.

Mass = 4.6g/1000 = 0.0046 kg

a. KE1 = 0.5*M*V1^2 = 3.13 J.

b. KE@ = 0.0023*74.8^2 = 12.87 J.

To calculate the kinetic energy of a moving object, you can use the formula:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Let's start with part A:

Given:
Mass of the first bullet (m1) = 4.6 g = 0.0046 kg
Velocity of the first bullet (v1) = 36.9 m/s

Using the kinetic energy formula, we can calculate part A:

KE1 = (1/2) * m1 * v1^2
= (1/2) * 0.0046 kg * (36.9 m/s)^2
= 0.5 * 0.0046 kg * 1360.61 m^2/s^2
≈ 1.573 J

So, the kinetic energy of the first bullet is approximately 1.573 J.

Now let's move on to part B:

Given:
Mass of the second bullet (m2) = 4.6 g = 0.0046 kg
Velocity of the second bullet (v2) = 74.8 m/s

Using the kinetic energy formula, we can calculate part B in a similar way:

KE2 = (1/2) * m2 * v2^2
= (1/2) * 0.0046 kg * (74.8 m/s)^2
= 0.5 * 0.0046 kg * 5592.04 m^2/s^2
≈ 12.900 J

Therefore, the kinetic energy of the second bullet is approximately 12.900 J.

So, the answers to the given questions are:
a) The kinetic energy of the first bullet is approximately 1.573 J.
b) The kinetic energy of the second bullet is approximately 12.900 J.