Y =-( x+2)² - 4 state clearly intercept x and intercept Y
clearly the vertex of this parabola is (-2,-4) and it opens downwards.
This is cannot possible reach the x-axis, thus no x-intercepts
for the y-intercepts, in you head let x = 0 and evaluated to get
y = -4-4 = -8
Let me type this again in proper English.
(Can I blame it on my keyboard ? )
Clearly the vertex of this parabola is (-2,-4) and it opens downwards.
Thus it cannot possible reach the x-axis, thus there are no x-intercepts
for the y-intercept, in you let let x = 0 and evaluate it, you get
y = -4-4 = -8
Sorry solve this y=1/2ײ-×-4
To find the intercepts of the equation Y = -(x + 2)² - 4, we need to determine at which points the equation intersects the x-axis (x-intercepts) and the y-axis (y-intercepts).
First, let's find the x-intercept(s), which are the points where the graph of the equation crosses the x-axis. At these points, the value of Y is zero.
Setting Y = 0 in the equation, we can solve for x:
0 = -(x + 2)² - 4
To simplify the equation, let's remove the negative sign by multiplying both sides by -1:
0 = (x + 2)² + 4
Now, subtract 4 from both sides:
-4 = (x + 2)²
Take the square root of both sides, considering both positive and negative roots:
±√(-4) = ±(x + 2)
Since the square root of a negative number is imaginary, there are no real x-intercepts for this equation. Therefore, the equation does not intersect the x-axis.
Next, let's find the y-intercept(s), which are the points where the graph of the equation crosses the y-axis. At these points, the value of x is zero.
Setting x = 0 in the equation, we can solve for Y:
Y = -(0 + 2)² - 4
Y = -(2)² - 4
Y = -4 - 4
Y = -8
So, the y-intercept is (0, -8).
In summary, the given equation does not have any x-intercepts but has a y-intercept at (0, -8).